ONLY A GUNIOUS CAN ANSWER IT
Hello friends,
How are you all? Hope everyone enjoying their life to the fullest.
After around 4 or 5 days i am back with a tricky question and wants the answer from you all.
So without any delay here is the puzzle......
somewhere in the wonder land there are sequence of 7 Temples separated by 7 rivers,
Sequence is Temple, River, Temple, River…………
A man has to put equal number of flowers on every temple but the catch is as he crossed the river, remaining flowers will be doubled (2 times)
how many flowers should a man carry with him before entering into first temple so that till last river he has left with nothing?
#Assume he took 5 flowers,
on first temple he drop 2, remaining is 3 as he crossed the river it will become 6, he put same number of flowers (i.e 2 flowers) 6-2=4 which again become twice in second river means 8…
I am trying to solve it so meanwhile i am giving this challange to you all and hope you may solve this puzzle.
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